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C Program to find Smallest element in the array

Get array size n and n elements of array, then find the smallest element among those elements.

Sample Input 1:

5 5 7 9 3 1

Sample Output 1:

1

Try your Solution

Strongly recommended to Solve it on your own, Don't directly go to the solution given below.

#include<stdio.h> int main() { //write your code here }

Program or Solution

				
			
					
#include<stdio.h>
#include<stdlib.h>
int main()
{
	int *a,n,i,min;
	printf("Enter size of array:");
	scanf("%d",&n);

	a=malloc(sizeof(int)*n);
	printf("Enter %d Elements:",n);
	for(i=0;i<n;i++)
	{
		scanf("%d",&a[i]);
	}
	
	min=a[0];
	
	for(i=1;i<n;i++)
	{
		if(a[i]<min)
		{
			min=a[i];
		}
		
	}

	printf("%d",min);
	return 0;		
}

Program Explanation

i is initialized to 0 and incremented by 1 at each iteration of both the for loops.

First for loop reads n input numbers from user and stores them in array a[] from location 0 to n-1 Initially assign the element located at 0 to max using min = a[0].

using second for loop visit each location serially from 1 to n-1.

if the element located in any position is lesser than min, then assign the element as max by using min = a[i] finally min holds the minimum value in the list.

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