C Program to check whether ith bit in a number N is set or not

Description

Get a number n and bit I, check whether ith bit in num is set or not.
Input:
8 3
Output:
Not Set

Input:
8 1
Output:
Set
Explanation:
0000 1000

Solution

#include<stdio.h>
int main()
{
	int num,bit;
	printf("Enter a number and a bit:");
	scanf("%d %d",&num,&bit);
	num=num>>(bit-1);
	if((num&1)!=0)
	{
		printf("%d is set",bit);
	}
	else
	{
		printf("%d is reset",bit);
	}
	return 0;
}

Explanation

left shift the number num by n-1 times move the nth bit to LSB.
Do AND operation between num and 1, if the LSB is 1 then output is 1, if LSB is 0 then output is 0.