C Program to calculate sum of N positive numbers(Skip the negative number and get another instated of that)

Description

Get input n and n postive integers (skip the negative number), then compute the sum of postive integers
Input:
5
6 7 2 -8 1 8
Ouput:
24

Solution

#include<stdio.h>
int main()
{
	int n,i,num,sum=0;
	printf("Enter number of numbers to sum:");
	scanf("%d",&n);
	i=0;
	printf("Enter %d number to sum:",n);
	while(i<n)
	{
		scanf("%d",&num);
		if(num>=0)
		{
			sum=sum+num;
			i++;	
		}
	
	}
	printf("The sum is : %d",sum);
	return 0;
}

Explanation

user should give n postive integers, if user entered negative number continue statement skips the count and sum statements. So this program gets n postive numbers and sum them.

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