C Program to get and print the array elements using pointers

Description

Get array size n and n elements of array, then print the elements.
Input:
5
5 7 9 3 1
Output:
5 7 9 3 1

Solution

#include<stdio.h>


#include<stdlib.h>
int main(void)

{
	
	int n,i,*a;

	printf("Enter size of array:");
	scanf("%d",&n);

	a=calloc(sizeof(int),n);
	printf("Enter %d Elements:",n);
	for(i=0;i<n;i++)

	{

		scanf("%d",a+i);

	}

	printf("Array elements are:\n");
	for(i=0;i<n;i++)
	
	{

		printf("%d ",*(a+i));

	}
	
	return 0;

}

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Explanation

calloc() is predefined function allocates memory of specified bytes.
Number of bytes is specified as (4,n), it means n 4 bytes. Since we are using integers, specified as 4bytes.

*a denotes first four bytes,  *(a+1) denotes second four bytes, *(a+2) denotes third four bytes and so on.,


i is initialized to 0 and incremented by 1 at each iteration of both the for loops.

First for loop reads n input numbers from user and stores them in array a[] from location 0 to n-1

Second for loop prints the n elements of array located from 0 to n-1.
Ramesh P Natarajan

Author - Ramesh P Natarajan

Software Developer and Technology Trainer, very much passionate in the field of Software Application Development, Machine Learning and Search Engine Optimization.

Write to: [email protected]





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