## circular list rotation in python

### Description

```Python Program to get list size n and n elements of list, rotate the elements of list in left side for m times.
Input:
5
5 7 9 3 1
2
Output:
9 3 1 5 7```

### Solution

```l=list(map(int,input("Enter numbers:").split(" ")))
r=int(input("Roatations?:"))
for i in range(0,r):
temp=l[0]
for j in range(0,len(l)-1):
l[j]=l[j+1]
l[len(l)-1]=temp
print(l)

```

### Explanation

```repeat the below steps for r times:

store the l[0] in temp
temp=l[0]

move all elements located in 1 to len(l)-1 to its previous location
l[j]=l[j+1]

store the temp in l[len(l)-1]
l[len(l)-1]=temp```

#### Author - Ramesh P Natarajan

Learner, Professor, Technology Trainer, Software Developer and Content Marketer, very much passionate in the field of Software Application Development, Machine Learning and Search Engine Optimization.

Write to: [email protected]

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