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Find the Missing Number in Array

Get an array of Integers arr[] with size n and find the first missing natural number in the array arr[].The array does not contains duplicates.

Example

Input 1:

5

4 5 3 1 6

Output 1:

2

Input 1:

6

4 5 3 2 6 7

Output 1:

1

Try your Solution

Strongly recommended to Solve it on your own, Don't directly go to the solution given below.

public class Hello { public static void main(String args[]) { //Write your code here } }

Program or Solution

				
				
					
import java.util.*;
class Missing_Number
{
	public static void main(String args[])
    	{

		//Variable and  Object Declarations
       		Scanner input = new Scanner(System.in);
		int n;
		
		//Getting size of Array & Declare Array arr[]
		n = input.nextInt();
		int arr[] = new int[n];

		//Get n values to array arr[]
		for(int i = 0; i<n; i++)
		{
			arr[i] = input.nextInt();
		}

		
		Arrays.sort(arr);
		for(int i = 0; i<n; i++)
		{
			
			if(i+1!=arr[i])
			{
				System.out.print(i+1);	
				break;
			}
		}
	
		
		
		
		
      	}
}

Program Explanation

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