C Program to check whether given Integer is Armstrong or Not

Description

Sample Input:
370
Sample Output:
ArmStrong (3*3*3 + 7*7*7 + 0=370)
Note: Cube digits for 3 digit numbers,  square digits for two digit number and soon.

Solution

#include<stdio.h>
int main()
{
	int n,num,count,rem,i,m,k=0;
	scanf("%d",&num);
	n=num;
	while(num!=0)
	{
		num/=10;
		count++;
	}
	num=n;
	while(num!=0)
	{
		rem=num%10;
		m=1;
		for(i=1;i<=count;i++)
		{
			m*=rem;
		}
		k+=m;
		num=num/10;
	}
	if(n==k)
	{
		printf("Armstrong Number");
	}
	else
	{
		printf("Not ArmStrong Number");
	}
	return 0;
	
}
		

Explanation

refer video tutorial



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