C Program to check whether given Integer is Armstrong or Not

Description

```Sample Input:
370
Sample Output:
ArmStrong (3*3*3 + 7*7*7 + 0=370)
Note: Cube digits for 3 digit numbers,  square digits for two digit number and soon.```

Solution

```#include<stdio.h>
int main()
{
int n,num,count,rem,i,m,k=0;
scanf("%d",&num);
n=num;
while(num!=0)
{
num/=10;
count++;
}
num=n;
while(num!=0)
{
rem=num%10;
m=1;
for(i=1;i<=count;i++)
{
m*=rem;
}
k+=m;
num=num/10;
}
if(n==k)
{
printf("Armstrong Number");
}
else
{
printf("Not ArmStrong Number");
}
return 0;

}
```

Explanation

`refer video tutorial`

Author - Ramesh P Natarajan

Learner, Professor, Technology Trainer, Software Developer and Content Marketer, very much passionate in the field of Software Application Development, Machine Learning and Search Engine Optimization.

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