## C Program to find Smallest element in the array using pointers

### Description

```Get array size n and n elements of array, then find the smallest element among those elements.
Input:
5
5 7 9 3 1
Output:
1```

### Solution

```#include<stdio.h>
#include<stdlib.h>
int main()
{
int *a,n,i,min;
printf("Enter size of array:");
scanf("%d",&n);

a=calloc(sizeof(int),n);
printf("Enter %d Elements:",n);
for(i=0;i<n;i++)
{
scanf("%d",a+i);
}

min=*a;

for(i=1;i<n;i++)
{
if(*(a+i)<min)
{
min=*(a+i);
}

}

printf("%d",min);
return 0;
}```

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### Explanation

```calloc() is predefined function allocates memory of specified bytes.
Number of bytes is specified as (4,n), it means n 4 bytes. Since we are using integers, specified as 4bytes.

*a denotes first four bytes,  *(a+1) denotes second four bytes, *(a+2) denotes third four bytes and so on.,
i is initialized to 0 and incremented by 1 at each iteration of both the for loops.

First for loop reads n input numbers from user and stores them in array a[] from location 0 to n-1

Initially assign the element located at 0 to max using min =*a.

using second for loop visit each  location serially from 1 to n-1. if the element located in any position is lesser than min,  then assign the element as max by using min = *(a+i)

finally min holds the minimum value in the list.```

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