C Program to find the sum of array elements using pointers

Description

Get array size n and n elements of array, then compute sum of the elements.
Input:
5
5 7 9 3 1
Output:
25

Solution

#include <stdio.h>


#include <stdlib.h>
int main(void)

{
	
	
	int n,i,*a,sum=0;

	printf("Enter size of array:");
	scanf("%d",&n);

	a=calloc(sizeof(int),n);
	printf("Enter %d Elements:",n);
	for(i=0;i<n;i++)

	{

		scanf("%d",a+i);

	}

	for(i=0;i<n;i++)
	
	{

		sum=sum+*(a+i);

	}

	printf("The sum of Array is: %d",sum);	
	return 0;

}

Explanation

calloc() is predefined function allocates memory of specified bytes.
Number of bytes is specified as (4,n), it means n 4 bytes. Since we are using integers, specified as 4bytes.

*a denotes first four bytes,  *(a+1) denotes second four bytes, *(a+2) denotes third four bytes and so on.,
i is initialized to 0 and incremented by 1 at each iteration of both the for loops.

First for loop reads n input numbers from user and stores them in array a[] from location 0 to n-1

Second for loop adds all the n elements of array located from 0 to n-1

Finally prints the sum using printf statement.



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