## Java Program to find Smallest element in the array

### Description

```Get array size n and n elements of array, then find the smallest element among those elements.
Input:
5
5 7 9 3 1
Output:
1```

### Solution

```import java.util.*;
class SmaArr
{
public static void main(String args[])
{
int size,i,num;
Scanner sc=new Scanner(System.in);
System.out.println("Enter Size Of Array:");
size=sc.nextInt();
int a[]=new int[100];
System.out.println("Enter The Array Elements:\n");
for(i=0;i<size;i++)
{
a[i]=sc.nextInt();

}
int min=a[0];
for(i=0;i<size;i++)
{
if(a[i]<min)
{
min=a[i];
}

}
System.out.println("The Smallest Element In The Array Is:"+min);
}
}
```

### Explanation

```i is initialized to 0 and incremented by 1 at each iteration of both the for loops.

First for loop reads n input numbers from user and stores them in array a[] from location 0 to n-1

Initially assign the element located at 0 to max using min = a[0].

using second for loop visit each  location serially from 1 to n-1. if the element located in any position is lesser than min,  then assign the element as max by using min = a[i]

finally min holds the minimum value in the list.```

#### Author - Ramesh P Natarajan

Learner, Professor, Technology Trainer, Software Developer and Content Marketer, very much passionate in the field of Software Application Development, Machine Learning and Search Engine Optimization.

Write to: [email protected]

### Interesting Pattern Programs: for more Patterns

```Input:
5
Output:
*
**
***
****
*****
****
***
**
*Solution```
```Input:
5
Output:
*
***
*****
*******
*********
*******
*****
***
*Solution```
```Input:
5
Output:
*        *
**      **
***    ***
****  ****
**********Solution```
```Input:
5
Output:
*       *
**     **
***   ***
**** ****
*********Solution```
```Input:
5
Output:
*       *
**     **
***   ***
**** ****
*********
**** ****
***   ***
**     **
*       *Solution```
```Input:
5
Output:
*********
*******
*****
***
*
***
*****
*******
*********Solution```