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Reverse the second half of list elements in python

Python Program to get list size n and n elements of list, then reverse the second n/2 elements.

Sample Input 1:

5 5 7 9 3 1

Sample Output 1:

5 7 1 3 9

Try your Solution

Strongly recommended to Solve it on your own, Don't directly go to the solution given below.

#write your code here

Program or Solution

				
			
					
l=list(map(int,input("Enter Numbers:").split()))
start=len(l)//2
stop=len(l)-1
while(start<stop):
    l[start],l[stop]=l[stop],l[start]
    start+=1
    stop-=1
print(l)

Program Explanation

initialize start to first location of list and stop to last location of list using start=len(l)/2 stop=len(l)-1 swap the elements in location start and stop, then increment start by 1 and decrement stop by 1. l[start],l[stop]=l[stop],l[start] repeat the above step till start is less than stop

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