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circular list rotation in python

Python Program to get list size n and n elements of list, rotate the elements of list in left side for m times.

Sample Input 1:

5 5 7 9 3 1 2

Sample Output 1:

9 3 1 5 7

Program or Solution

					    
							
l=list(map(int,input("Enter numbers:").split(" ")))
r=int(input("Roatations?:"))
for i in range(0,r):
    temp=l[0]
    for j in range(0,len(l)-1):
        l[j]=l[j+1]
    l[len(l)-1]=temp
print(l)
        
    



					    
					

Program Explanation

repeat the below steps for r times: store the l[0] in temp temp=l[0] move all elements located in 1 to len(l)-1 to its previous location l[j]=l[j+1] store the temp in l[len(l)-1] l[len(l)-1]=temp