circular list rotation in python
Python Program to get list size n and n elements of list, rotate the elements of list in left side for m times.
Sample Input 1:
5 5 7 9 3 1 2
Sample Output 1:
9 3 1 5 7
Program or Solution
l=list(map(int,input("Enter numbers:").split(" ")))
r=int(input("Roatations?:"))
for i in range(0,r):
temp=l[0]
for j in range(0,len(l)-1):
l[j]=l[j+1]
l[len(l)-1]=temp
print(l)
Program Explanation
repeat the below steps for r times: store the l[0] in temp temp=l[0] move all elements located in 1 to len(l)-1 to its previous location l[j]=l[j+1] store the temp in l[len(l)-1] l[len(l)-1]=tempComments
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