C Program to Reverse the Elements in array

Description

```Get array size n and n elements of array, then reverse the n elements.
Input:
5
5 7 9 3 1
Output:
1 3 9 7 5```

Solution

```#include <stdio.h>
#include <stdlib.h>

int main(void)

{

int *a,n,i,j,temp;

printf("Enter size of array:");
scanf("%d",&n);

a=malloc(sizeof(int)*n);

printf("Enter %d Elements:",n);
for(i=0;i<n;i++)

{

scanf("%d",&a[i]);

}

for(i=0,j=n-1;i<j;i++,j--)

{

temp=a[i];
a[i]=a[j];
a[j]=temp;
}

printf("\After reversing the array:\n");
for(i=0;i<n;i++)

{

printf("%d ",a[i]);

}

return 0;

}```

Explanation

```initialize i to first location of array and j to last location of array using
i=0
j=n-1

swap the elements in location i and j, then increment i by 1 and decrement j by 1.
t=a[i]
a[i]=a[j]
a[j]=temp

repeat the above step till i is less than j ```

Author - Ramesh P Natarajan

Learner, Professor, Technology Trainer, Software Developer and Content Marketer, very much passionate in the field of Software Application Development, Machine Learning and Search Engine Optimization.

Write to: [email protected]

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