## C Program to Search an Element in an array

### Description

```Get an element and find the location of element in array, print -1 if element is not found.
Input:
5
5 7 9 3 1
9
Output:
2
Input:
5
5 7 9 3 1
4
Output:
-1```

### Solution

```#include <stdio.h>
#include <stdlib.h>

int main(void)

{

int *a,n,i,pos=-1,element;

printf("Enter size of array:");
scanf("%d",&n);

a=malloc(sizeof(int)*n);

printf("Enter %d Elements:",n);
for(i=0;i<n;i++)

{

scanf("%d",&a[i]);

}

printf("Enter a element to find:");
scanf("%d",&element);

for(i=0;i<n;i++)

{

if(a[i]==element)
{
pos=i;
break;
}
}

printf("%d is in %d",element,pos);
return 0;

}```

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### Explanation

```i is initialized to 0 and incremented by 1 at each iteration of both the for loops.

First for loop reads n input numbers from user and stores them in array a[] from location 0 to n-1

using Second for loop the element is searched in each location from 0 to  the location of element or location n-1.

if element is found in a location that location i is stored as pos and exit from the for loop using break statement.

if element is not found from 0 to n-1 location, pos remains -1.```

#### Author - Ramesh P Natarajan

Software Developer and Technology Trainer, very much passionate in the field of Software Application Development, Machine Learning and Search Engine Optimization.

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