# C Program to find Second smallest element in the array

Get array size n and n elements of array, then find the second smallest element among those elements.

Sample Input 1:

5 5 7 9 3 1

Sample Output 1:

3

#### Program or Solution

``` #include<stdio.h> #include<stdlib.h> #include<limits.h> int main() { int *a,n,i,min,second_min; printf("Enter size of array:"); scanf("%d",&n); a=malloc(sizeof(int)*n); printf("Enter %d Elements:",n); for(i=0;i<n;i++) { scanf("%d",&a[i]); } min=INT_MAX; second_min=INT_MAX; for(i=0;i<n;i++) { if(a[i]<min) { second_min=min; min=a[i]; } else if(a[i] < second_min && a[i]!=min) { second_min=a[i]; } } printf("The second minimum is : %d",second_min); return 0; } ```

#### Program Explanation

Initialize min and second_min with INT_MAX(INT_MAX is constant holds maximum integer value) visit every location in the array a) If the current element in array a[i] is less than min.

Then update min and second_min as, second_min = min min = a[i] b) If the current element is greater than min and less than second_min, then update second_min to store the value of current variable as second_min = arr[i] print the value stored in second_min.

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