# C Program to find Smallest element in the array

Get array size n and n elements of array, then find the smallest element among those elements.

Sample Input 1:

5 5 7 9 3 1

Sample Output 1:

1

#### Program or Solution

` ````
#include<stdio.h>
#include<stdlib.h>
int main()
{
int *a,n,i,min;
printf("Enter size of array:");
scanf("%d",&n);
a=malloc(sizeof(int)*n);
printf("Enter %d Elements:",n);
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
min=a[0];
for(i=1;i<n;i++)
{
if(a[i]<min)
{
min=a[i];
}
}
printf("%d",min);
return 0;
}
```

#### Program Explanation

i is initialized to 0 and incremented by 1 at each iteration of both the for loops.

First for loop reads n input numbers from user and stores them in array a[] from location 0 to n-1 Initially assign the element located at 0 to max using min = a[0].

using second for loop visit each location serially from 1 to n-1.

if the element located in any position is lesser than min, then assign the element as max by using min = a[i] finally min holds the minimum value in the list.