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C Program to Arithmetic Calculator using switch case Statements
Get a binary arithmetic expression and solve the expression.
Sample Input 1:
12+9
Sample Output 1:
21
Sample Input 2:
4*5
Sample Output 2:
20
Program or Solution
#include<stdio.h>
int main()
{
int num1,num2,output;
char operator;
printf("Enter a binary expression:");
scanf("%d %c %d",&num1,&operator,&num2);
switch(operator)
{
case '+':
output=num1+num2;
break;
case '-':
output=num1-num2;
break;
case '*':
output=num1*num2;
break;
case '/':
output=num1/num2;
break;
case '%':
output=num1%num2;
break;
default :
printf("invalid operation");
break;
}
printf("%d",output);
return 0;
}
Program Explanation
Based on the second character operator, instructions in any one of the case will be executed.