Leap year in python
Python Program to get a year and check whether year is leap year or not.
Sample Input 1:
2016
Sample Output 1:
Leap year
Sample Input 2:
2017
Sample Output 2:
Not Leap Year
Program or Solution
year = int(input("Enter a year: "))
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print("{0} is a leap year".format(year))
else:
print("{0} is not a leap year".format(year))
else:
print("{0} is a leap year".format(year))
else:
print("{0} is not a leap year".format(year))
Program Explanation
Get input year from user using input() method,
All the years divisible by 4 are leap year except century years. Century years are leap year if it is divisible by 400.
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