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Leap year in python

Python Program to get a year and check whether year is leap year or not.

Sample Input 1:

2016

Sample Output 1:

Leap year

Sample Input 2:

2017

Sample Output  2:

Not Leap Year

Try your Solution

Strongly recommended to Solve it on your own, Don't directly go to the solution given below.

#write your code here

Program or Solution

				
				
					
year = int(input("Enter a year: "))
if (year % 4) == 0:
   if (year % 100) == 0:
       if (year % 400) == 0:
           print("{0} is a leap year".format(year))
       else:
           print("{0} is not a leap year".format(year))
   else:
       print("{0} is a leap year".format(year))
else:
   print("{0} is not a leap year".format(year))

Program Explanation

Get input year from user using input() method,

All the years divisible by 4 are leap year except century years. Century years are leap year if it is divisible by 400.  

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