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Count the number of digits in a Number in Python

Write a program to count the number of digits of a given number.

Sample Input 1:

345

Sample Output 1:

3

Sample Input 2:

56

Sample Output 2:

2


Program or Solution

				
				
					
n = int(input())
count  = 0
while  n > 0:
    n = n // 10
    count = count + 1
print(count)

Program Explanation

if we divide a number by 10, then last digit of the same number will removed and we get remaining digits as output. Do the same till number becomes 0 and count iteration. So the count is number of digits of the given number .

Comments

NAVEEN@03012000
pls provide logical program for this provide lot of example for this program

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