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C Program to Reverse the Elements in array using pointers

Get array size n and n elements of array, then reverse the n elements.

Sample Input 1:

5 5 7 9 3 1

Sample Output 1:

1 3 9 7 5

Program or Solution

#include <stdio.h>

#include <stdlib.h>
int main()

	int *a,n,i,j,temp;

	printf("Enter size of array:");

	printf("Enter %d Elements:",n);






	printf("After reversing the array:\n");




	return 0;



Program Explanation

calloc() is predefined function allocates memory of specified bytes

Number of bytes is specified as (4,n), it means n 4 bytes.

Since we are using integers, specified as 4 bytes.

*a denotes first four bytes, *(a+1) denotes second four bytes, *(a+2) denotes third four bytes and so on., initialize i to first location of array and j to last location of array using i=0 j=n-1

swap the elements in location i and j, then increment i by 1 and decrement j by 1.

 t=*(a+i)*(a+i)=*(a+j) *(a+j)=temp repeat the above step till i is less than j