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C Program to Search an Element in an array using Pointers

Get an element and find the location of element in array, print -1 if element is not found.

Sample Input 1:

5 5 7 9 3 1 9

Sample Output 1:


Sample Input 2:

5 5 7 9 3 1 4

Sample Output 2:


Program or Solution

#include <stdio.h>

#include <stdlib.h>
int main(void)

	int n,i,pos=-1,*a,element;

	printf("Enter size of array:");

	printf("Enter %d Elements:",n);




	printf("Enter a element to find:");



	printf("%d is in %d",element,pos);	
	return 0;



Program Explanation

calloc() is predefined function allocates memory of specified bytes.

Number of bytes is specified as (4,n), it means n 4 bytes.

Since we are using integers, specified as 4 bytes.

*a denotes first four bytes, *(a+1) denotes second four bytes, *(a+2) denotes third four bytes and so on., i is initialized to 0 and incremented by 1 at each iteration of both the for loops.

 First for loop reads n input numbers from user and stores them in array a[] from location 0 to n-1  using Second for loop the element is searched in each location from 0 to the location of element or location n-1.

if element is found in a location that location i is stored as pos and exit from the for loop using break statement.

 if element is not found from 0 to n-1 location, pos remains -1.