C Program to set or reset a bit in number

Description

Get a number n and bit b, n is a number and b denotes any bit postion of n. set b postion of n as 1 if it is 0, reset b postion of n as 0 if it is 1.
Sample Input 1:
4 1
Sample Output 1:
5
Note:
4->0000 0100
After seting 1st Pos: 0000 0101
So output is 5.

Solution

#include<stdio.h>
int main()
{
	int num,bit,n;
	printf("Enter a number and a bit:");
	scanf("%d %d",&num,&bit);
	n=1<<(bit-1);
	num=num^n
	printf("The value after %d bit is: %d",bit,num);
	return 0;
}

Explanation

Get a number num and bit as input  (using scanf statement)

left shift 1 by bit times (n=1<			


			


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