C Program to toggle a bit in number
Get a number n and bit b, n is a number and b denotes any bit postion of n. set b postion of n as 1 if it is 0, reset b postion of n as 0 if it is 1.
Sample Input 1:
4 1
Sample Output 1:
5 Note: 4->0000 0100 After seting 1st Pos: 0000 0101 So output is 5.
Try your Solution
Strongly recommended to Solve it on your own, Don't directly go to the solution given below.
#include<stdio.h>
int main()
{
//write your code here
}
Program or Solution
#include<stdio.h>
int main()
{
int num,bit,n;
printf("Enter a number and a bit:");
scanf("%d %d",&num,&bit);
n=1<<(bit-1);
num=num^n
printf("The value after %d bit is: %d",bit,num);
return 0;
}
Program Explanation
Get a number num and bit as input (using scanf statement) left shift 1 by bit times (n=1<Comments
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